Tuesday, 11 August 2015

EKO - Eko

EKO - Eko

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Lumberjack Mirko needs to chop down M metres of wood. It is an easy job for him since he has a nifty 
new woodcutting machine that can take down forests like wildfire. However, Mirko is only allowed to 
cut a single row of trees.
Mirko‟s machine works as follows: Mirko sets a height parameter H (in metres), and the machine raises 
a giant sawblade to that height and cuts off all tree parts higher than H (of course, trees not higher than 
H meters remain intact). Mirko then takes the parts that were cut off. For example, if the tree row 
contains trees with heights of 20, 15, 10, and 17 metres, and Mirko raises his sawblade to 15 metres, the 
remaining tree heights after cutting will be 15, 15, 10, and 15 metres, respectively, while Mirko will take 
5 metres off the first tree and 2 metres off the fourth tree (7 metres of wood in total).
Mirko is ecologically minded, so he doesn‟t want to cut off more wood than necessary. That‟s why he 
wants to set his sawblade as high as possible. Help Mirko find the maximum integer height of the 
sawblade that still allows him to cut off at least M metres of wood.
Lumberjack Mirko needs to chop down M metres of wood. It is an easy job for him since he has a nifty 
new woodcutting machine that can take down forests like wildfire. However, Mirko is only allowed to 
cut a single row of trees.
Mirko‟s machine works as follows: Mirko sets a height parameter H (in metres), and the machine raises 
a giant sawblade to that height and cuts off all tree parts higher than H (of course, trees not higher than 
H meters remain intact). Mirko then takes the parts that were cut off. For example, if the tree row 
contains trees with heights of 20, 15, 10, and 17 metres, and Mirko raises his sawblade to 15 metres, the 
remaining tree heights after cutting will be 15, 15, 10, and 15 metres, respectively, while Mirko will take 
5 metres off the first tree and 2 metres off the fourth tree (7 metres of wood in total).
Mirko is ecologically minded, so he doesn‟t want to cut off more wood than necessary. That‟s why he 
wants to set his sawblade as high as possible. Help Mirko find the maximum integer height of the 
sawblade that still allows him to cut off at least M metres of wood.

Input


The first line of input contains two space-separated positive integers, N (the number of trees, 1 ≤ N ≤ 
1 000 000) and M (Mirko‟s required wood amount, 1 ≤ M ≤ 2 000 000 000).
The second line of input contains space-separated positive integers less than 1 000 000 000, the 
heights of each tree (in metres). The sum of all heights will exceed M, thus Mirko will always be able to 
obtain the required amount of wood.

Output

The first and only line of output must contain the required height setting.

Example

Input:
4 7
20 15 10 17

Output:
15
Input:
5 20
4 42 40 26 46
Output:
36

xmasma

#include<iostream>
#include<stdio.h>
#include<algorithm>
using namespace std;
long long int read_int(){
char r;
bool start=false,neg=false;
long long int ret=0;
while(true){
r=getchar();
if((r-'0'<0 || r-'0'>9) && r!='-' && !start){
continue;
}
if((r-'0'<0 || r-'0'>9) && r!='-' && start){
break;
}
if(start)ret*=10;
start=true;
if(r=='-')neg=true;
else ret+=r-'0';
}
if(!neg)
return ret;
else
return -ret;
}
 int  main()
 {
 long long int  tr,m;
  // cin>>tr>>m;
  tr=read_int();
  m=read_int();
   long long int  arr[tr+10],max_gain=0;
    for(long long int  i=0;i<tr;i++)
     {
      //cin>>arr[i];
      arr[i]=read_int();
     }
     sort(arr,arr+tr);
     long long int  lo=arr[0];
     long long int  mid;
     long long int  hi=arr[tr-1];
     while(lo<hi)
      {
      mid=(lo+hi)/2;
      long long int  sum=0;
      for(long long int  i=0;i<tr;i++)
      {
      if(arr[i]>mid)
      sum+=(arr[i]-mid);
      }
     
      if(sum==m)
      {
      cout<<mid<<endl;
      return 0;
      }
     
        else if(sum<m)
        {
         hi=mid;
        }
        else
        {
        if(max_gain<mid) max_gain=mid;
        lo=mid+1;
       
        }
     
     
      }
      cout<<max_gain<<endl;
  return 0;
 }

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